solvecost_power {tidywater} | R Documentation |
Determine power cost
Description
This function takes kW, % utilization, $/kWhr and determines power cost.
Usage
solvecost_power(power, utilization = 100, cost, time = "day")
Arguments
power |
Power consumed in kW |
utilization |
Amount of time equipment is running in percent. Defaults to continuous. |
cost |
Power cost in $/kWhr |
time |
Desired output units, one of c("day", "month", "year"). Defaults to "day". |
Value
A numeric value for power, $/time.
Examples
powercost <- solvecost_power(50, 100, .08)
library(dplyr)
cost_data <- tibble(
power = seq(10, 50, 10),
utilization = 80
) %>%
mutate(costs = solvecost_power(power = power, utilization = utilization, cost = .08))
[Package tidywater version 0.9.0 Index]